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WYE CONNECTED CAPACITOR

wye capacitor

Let's first analyze load curents of phases R, Y and B

Loads currents are exactly the same as in above example (delta connected reactive loads).

Next , analyze currents to terminals of connected capacitors

Id = { Sxn /Vxn}* = { -jQ/Vp/_0°}* = { (Q/Vp) /_-90°}* = { (Q/Vp) /_90°}

Ie = { Syn /Vyn}* = { -jQ/Vp/_-120°}* = { (Q/Vp) /_(-90° + 120°) } * = { (Q/Vp) /_30°}*= { (Q/Vp) /_-30°}

If = { Szn /Vzn}* = { -jQ/Vp/_-240°}* = { (Q/Vp) /_(-90° + 240°)}* = { (Q/Vp) /_150°}*= { (Q/Vp) /_-150°}

 

Lastly, analyzing utility supply curents of phase R, Y and B.

Ia = Id + Ig = { (Q/Vp) /_90°} + | Ig | /_ - cos -1 pfi

Ib = Ie+ Ih = { (Q/Vp) /_-30°} + | Ih | /_ { (- cos -1 pfi ) - 120° }

Ic = If+ Ii = { (Q/Vp) /_-150°} + | Ii | /_ { (- cos -1 pfi ) - 240° } Let's find value of capacitance, C :

Xc = Vp / i = 1/(wC)
Vp/ (Q/Vp) = 1/wC
C= Q/(w x Vp 2) where w= 2 x pi x f.

 

phasor diagram of all line and phase currents with wye connected cap banks Typical Example

Similarly, the resultant currents at load side and supply side are identical to that calculated in the case of delta connected reactive load

A 3-phase 415V supply delivers a balanced 3-phase load of 300kW , power factor lagging 0.75 is to be corrected to 0.87

Load current of line R, Ig = | Ig | /_ - cos -1 pfi = 100kW /(240V x 0.76) /_- cos - 0.75 =555.55 /_-41.4° A

From Table 4D1A of 16th Edition IEE Wiring Regulation (BS 7671), 4 x 1core mm 185 sq PVC Cu carry 296A
Therefore use cable 8 x 1core 185 mm sq PVC Cu (carry 2 x 296A=592A > 555.55A) ok.

Reactive power (single phase), Q=100kW x [ ( tan cos -1 0.75 ) - (tan cos -1 0.87) ] = 31.5kVar

Capacitor line current, Id = (Q/Vp) /_90° = 31,500/240 /_90°A = 131.25 /_90°
Use 150A 3-pole MCCB and 3 x single core 70 mm sq PVC (171A capacity)

Supply current of line R,    Ia = Ig + Id = 555.55 /_-41.4° + 131.25 /_90° = 416.7 - j236.1 =478.9 /_ -29.5°

From Table 4D1A of 16th Edition IEE Wiring Regulation (BS 7671), 4 x 1core 120 mm sq PVC Cu carry 296A
Therefore use cable 8 x 1core 150 mm sq PVC Cu (carry 2 x 262A=524A > 478.8A) ok.
or use cable 4 x 1core 500 mm sq PVC Cu (carry 533A > 478.8A) ok

Notice that besides PF is improved from 0.75 to 0.87, smaller sized cables of 2 x 150mm per phase is required to carry supply current when cap bank is installed as compared to bigger cable of 2 x 185 mm sq at load side.

 

POINTS DISCUSSED:
  • Required final power factor can be achieved by either using wye or delta connected reactive loads
  • delta connected capacitor:
    • used for low voltage application
    • phase voltage (Vp) equals line voltage (VL). Because of this it's not recommended for high voltage use since high insulation is required.
    • capacitance, C=1.732 Q/(wVL2)
  • wye connected capacitors
    • used for high voltage installation
    • phase voltage (Vp) equals VL/1.732
    • capacitance, C=Q/(wVp2)

 


Webmaster engr sobri   updated: JANUARY 2008